Which part of projector lens needs to "see" top of screen? (Trying to mount as high as possible) - AVS Forum
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Old 06-06-2012, 08:24 PM - Thread Starter
kal
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I have a bulkhead (soffit) between my projector and screen. I want to put the projector as high as possible.

Which is the correct drop distance to install the projector? Option 1, 2, or 3?:

mount1.jpg

mount2.jpg

mount3.jpg

(Image features exaggerated for effect)

I'm assuming with digital projectors it's option 1? (Because it's the entire lens that forms the image). Correct?

The projector in question will be a JVC RS45 or RS55.

Thanks!

Kal
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Old 06-06-2012, 09:07 PM
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Generally, the top of the lens because the lens is indented and the light scatters/spreads fairly immediately, but lens shift is going to move it a little, so it will depend on the angle as well as the distance from the lens to the bulkhead.

The way you figure this out is to use the formula below that I posted:
http://www.avsforum.com/t/1375094/official-jvc-x30-rs45-owners-thread/3240#post_21863092

Just measure the distance from the bulkhead to the projector lens, and use that formula to calculate the inches instead of feet (you'll just make a small adjustment to it).
Then you will know about how far it needs to clear it.


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Old 06-07-2012, 01:49 PM - Thread Starter
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I figured that the entire lens was used but thought I'd check anyway.

The formula makes a lot of sense. I ended up pulling a string and using a laser pointer to double check too. I need a 6" drop minimum for my given throw.

The mount's been ordered:

Chief RPMA281 (which includes the SLB281 plate to fit a RS45 or RS55)
Chief CMA101 "designer" ceiling plate
Chief CMS003 3" pipe (1.5" NPT)

All combined the drop's slightly more than 6".

Thanks for the help!

Kal
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