Originally Posted by Ugly1
Look Chris, I'm tired of responding to your statements in which you try to put words in my mouth, which posted evidence would support, I never said. You clearly have some gaping holes when it comes to knowing the theory behind this stuff.
And I've kept asking you to point out what exactly you disagree with, and you can't do that, you just keep saying I don't know what I'm talking about and I can't really discern what it is you have a problem with.
For example does this statement you made
somehow contradict mine which you felt the need to spend a paragraph addressing:
Then you said this:
That's because your statements are confusing, unclear, and I don't really know what it is your disagreement is even about.
Either you never read my response to your post or you like dwelling on the past but I conceded your point on this many many posts ago. Give it up already.
I did, but you are incoherent, so it's difficult to figure out what the heck you mean particularly when you are confusing so many things together.
You really seem to be struggling hard to point me out as being the devil and yet have not supporting evidence contradicting anything about my last post other than the school of Duvetynes hand waving.
I have no idea where you get that. I'm just attempting to explain the subject, briefly.
This is precisely what I'm reffering to when I suggest you don't get it. You should look at the link about UTP on wiki. Twisted pair does help in unbalanced circuits because it reduces differential noise.
No it doesn't. In an unbalanced circuit, one leg is ground. There is no common noise possible so there is no noise cancellation. How can it cancel out in an unbalanced circuit? The answer is that it can't, and that it doesn't, and that's why twisted pair doesn't do you a damn bit of good unless the circuit is balanced.
As for the links, I'm not sure what it is you are referring to that supports your idea that twisting the pair together somehow reduces noise by and of itself. It doesn't. It only helps if it is a balanced line. The Wikipedia article, rough as it is, does an alright job of explaining this. If you have an unbalanced line, there won't be any difference if you have an untwisted pair or a twisted pair, because the twist is only advantageous for common mode noise rejection which obviously only can occur in a balanced line.
Maybe you should ask yourself if you've ever heard of a perfect ground before?
I don't understand what you mean by this question. Do you mean too much resistance to ground? I'm not sure the relevance of what you are asking here.
They all have impedance which can and will be modulated by noise.
Again, what? What has impedance modulated by noise? This makes no sense at all.
Differential noise is a problem for unbalanced circuits too.
Bottom line is I have better things to do than go round and round about this stuff repeating myself. You clearly have some learning to do and don't appear to be willing to even listen to reason. The links are there, now you need to understand whats in them.
What links? What reason? You haven't even said anything that makes sense! The reason you're going around and around is because you're not constructing any kind of linear point here.
I fail to see why this topic is so difficult for you to understand. The pair twist only exists to make sure that noise is induced equally on both conductors, and the only reason this is beneficial is if it's a balanced line so it can cancel out. If it's not balanced, well then obviously is isn't going to cancel out is it! So the twist has no advantage at all! That's all I've been saying since page one, and apparently you can't accept this very simple premise. That's why you almost never see unshielded twisted pairs in anything but balanced lines, or for higher level signals where noise is not a concern.