Join Date: Sep 2004
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I am serious...and don't call me Shirley.
Bryan Pape - Lead Acoustician
|Originally posted by Peter_Klim
We all know any decent power amp will provide more power to a 4 ohm speaker load than a 8 ohm speaker load.
So, I would assume V(squared)/R is correct? But why are there 2 formulas for Power, where in one, increasing the Resistance lowers Power and in the other, decreasing Resistance increases Power?
|Originally posted by TonyBDA
"where in one, increasing the Resistance lowers Power and in the other, decreasing Resistance increases Power?
Both equations produce the same result, one uses resistance and voltage, the other, resistance and current. They're easy to prove.