OK, I think I understand what you're saying Darin. To restate it slightly differently, mathematically:
Normally y = g(x) = x^2.5, where 0 <= x <= 1
You're saying you have some IRE floor, let's call it c. For your real 1000:1 DLP projector, you want:
y = ( (x+c) / (1+c) )^2.5
For x=1, obviously y=1, regardless of c, and for x=0, you adjust c so that it matches the black level of your projector.
Let's say b is the black level of your projector, in your...