Originally Posted by Jinjuku
OMG... this is all happening on the x-over. It doesn't have anything to do with the bi-wiring. The bi-wire isn't high or low pass. It's simply power from the speaker
A good x-over design will make sure there is no back EMF from the drivers when they de-engergize (that is back to resting posistion). Again the bi-wire doesn't do anything to prevent that.
God has little to with this:
you can thank Léon Charles Thévenin and Gustav Robert Kirchhoff
yes it is, sort of....of a given frequency (actually it's voltage V and current i, the product, V x i, is power)
in the high pass wires, low freq current can't flow
in the low pass wires, high freq can't flow
they are excluded/reject/attenuated...
OK let's look at it like this:
say the amp is making 10W/ch (a given current and voltage, same imped, ie same speaker) the 10W power is comprised of hi and low freq signals, ie, music...
with 1 pair it carries 10W, 1 pair carries it all
with 2 pair it STILL carries 10W, it is somehow magically divided/proportioned between the 2
what divides it? perhaps the 'impedance' of the filters?
let's say that one pair the low pass carries 7, since bass needs more power and the high carries 10 - 7 ~ 3W...still with me?
now, how would the power be 'proportioned' in such a fashion?
how would the hi pass 'reject' 7W of power?
and the low pass reject 3W of the total 10W signal?
maybe it attenuates the lows (and the low pass accepts them), and vice versa...
now, according to your 'theory', both filters see and absorb the same power...
so you would need 10 + 10 ~ 20W if both filters see ALL of the freqs (current ~ power) in the signal...it doesn't, it only sees what the filters allow to flow through them, not UP to them...then the electrons just congregate there, lol
I'm done, I'll let the readers decide on the merits, and logic presented in the posts...an electrical engineer will understand, and I think anyone with a basic electrical understanding will...
time to listen to my new Miles Davis box set...have a nice day