Quote:
Originally Posted by mastermaybe 
He maintained: "assuming the projector is level, the image center will be aligned with the center of the lens. So in your case, 12" from the ceiling, you will have plenty of vertical shift to direct the top of the image down a few inches from the ceiling."
He added (reasonable so, assuming the above premise): "regardless of whether the projector is inverted or not, you're still going to have the lens centered with the image, with no lens shift".
Now in fairness, when he said that the PJ's lens is centered with the image I was feeling good about my chances too, as I formerly assumed the AR100 actually "threw" the image at a slightly upward angle (when placed right side up) and I would be unable to alter it enough with LS, but if it's in the "middle", then I'd only have to drag down the image about a foot after you consider the middle is already 12" from the ceiling and half of the screen height is ~21", + a 2" frame and a 1" space between the frame and ceiling.
So what am I missing if I may ask? Right now, at one foot from the ceiling I'm expecting 9" of the image to be projected on the ceiling, so I have to account for those 9 inches and the 3 inches for the frame and space between the frame and ceiling.
thanks for any help...I know this should not be this difficult.
James

He maintained: "assuming the projector is level, the image center will be aligned with the center of the lens. So in your case, 12" from the ceiling, you will have plenty of vertical shift to direct the top of the image down a few inches from the ceiling."
He added (reasonable so, assuming the above premise): "regardless of whether the projector is inverted or not, you're still going to have the lens centered with the image, with no lens shift".
Now in fairness, when he said that the PJ's lens is centered with the image I was feeling good about my chances too, as I formerly assumed the AR100 actually "threw" the image at a slightly upward angle (when placed right side up) and I would be unable to alter it enough with LS, but if it's in the "middle", then I'd only have to drag down the image about a foot after you consider the middle is already 12" from the ceiling and half of the screen height is ~21", + a 2" frame and a 1" space between the frame and ceiling.
So what am I missing if I may ask? Right now, at one foot from the ceiling I'm expecting 9" of the image to be projected on the ceiling, so I have to account for those 9 inches and the 3 inches for the frame and space between the frame and ceiling.
thanks for any help...I know this should not be this difficult.
James
I'll admit I didn't any math on this and if the tech says it will work then you've at least got a shot. I've never had a projector installed right side up. Guess you'll know soon enough.

























