Quote:
Originally Posted by AV Science Sales 5 
That 80% of screen height is from the center of the screen.
56" x 0.8 = 44.8"
44.8" - 28" (half screen height) = 16.8"
16.8" is the max the center of the lens can be above the image, if no horizontal lens shift is used. An easier way to calculate this is 56" x 0.3 = 16.8" . You never want to use all of the lens shift. The less lens shift you use, the better.

That 80% of screen height is from the center of the screen.
56" x 0.8 = 44.8"
44.8" - 28" (half screen height) = 16.8"
16.8" is the max the center of the lens can be above the image, if no horizontal lens shift is used. An easier way to calculate this is 56" x 0.3 = 16.8" . You never want to use all of the lens shift. The less lens shift you use, the better.

Thanks Mike, that helps a lot.
Another question that you or someone else can help with.
Ok, say I am going to have a 11' wide screen and use an anamorphic lens, and I want to stay near mid zoom to balance brightness on the one hand, and pin cushion on the other.
When looking at the projector central throw calculator, do I check the throw distance and zoom level by checking 16:9 (56" high / 100" wide), which as I understand it will be the zoomed/focused image, that will then be compressed and then widened by the anamorphic lens.
Or, do should I be looking at the throw distance in the calculator based on 2.35 - 56" high/ 132" wide?
When I use the PC calculator base on 16:9 (100" wide), mid zoom is about 16' (I would probably opt for longer to minimize pin cushion and room placement).
However, when I chance the PC calculator to 2.35 (132" wide), mid zoom winds up being about 21'.
My thinking is that if using an Anamorphic lens then the 16:9 (56" / 100") is what I should be using to get a ball park on the throw distance I can use. Correct?





















but with the corr. enabled the clock appears really perfect - like having no convergence issue! (could post some shots before/after, if desired)