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Originally Posted by hwjohn
 I don't know how much we can really do about that except double check the pattern, and it has already been triple checked for the most part.
Could you quantify how far off it is? That may at least give users an idea of how far off the filter based method is (I would guess it would also vary from filter to filter). If it is off less than 5% or so, I would call that pretty darn good. |
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XboxHD.zip 2.0830078125k . file
). The difference is only the rate at which the information is sent from one end to the other, the higher the information rate the higher your (potential) resolution will be. I was also not using quite the right terminology, for 480i the sampling frequency required is 13.5 MHz while the nyquist frequency is 6.75 MHz. The bandwidth is usually kept somewhat below the nyquist frequency to avoid distortion near nyquist.
). The above pattern would be completely blurred to gray. However, we would be able to represent a pattern like this:
). The above pattern would be completely blurred to gray. However, we would be able to represent a pattern like this:
f = ((2 * 3.141592653 * 1000000) / (74250000 / 1.001));
for(i = 0; i < 460; i++) {
value = sin(f * (double)i);
value = (value * 219 / 2) + (219 / 2) + 16;
y = (unsigned char)value;
buffer422[index++] = 0x80;
buffer422[index++] = y;
}
f = ((2 * 3.141592653 * 1000000) / (74250000 / 1.001));
for(i = 0; i < 460; i++) {
value = sin(f * (double)i);
value = (value * 219 / 2) + (219 / 2) + 16;
y = (unsigned char)value;
buffer422[index++] = 0x80;
buffer422[index++] = y;
}
f = ((2 * 3.141592653 * 1000000) / (74250000 / 1.001));
for(i = 0; i < 460; i++) {
value = sin(f * (double)i);
value = (value * 219 / 2) + (219 / 2) + 16;
y = (unsigned char)value;
buffer422[index++] = 0x80;
buffer422[index++] = y;
