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#### HeyNow^

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What are the width and length dimensions of a 61" 16:9 screen? And a 61" 4:3 screen?

#### DanTheMan

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Quote:
 Originally posted by RickZ: 61" 16:9 screen? Roughly 53" W by 30" H 61" 4:3 screen? Roughly 49" W by 37" H Based on x**2+y**2=z**2.
Now calculate the area of each screen:

16:9 screen = 53 * 30 = 1590 sq. in.

4:3 screen = 49 * 37 = 1813 sq. in.

So, maybe the "widescreen" should in reality be called the "short screen". http://www.avsforum.com/ubb/eek.gif

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#### RickZ

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You can fit a 65" 16:9 inside a 73" 4:3.

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#### RickZ

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61" 16:9 screen? Roughly 53" W by 30" H

61" 4:3 screen? Roughly 49" W by 37" H

Based on x**2+y**2=z**2.

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Turn the lights down and the sound up!

#### JohnHN

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Although the CaveCreations link will do all the calculations for you, sometimes it's helpful to be able to do quick calculations on the road, so ...

For 4:3 sets, for height multiply by 3/5 and for width multiply by 4/5. This is just the Pythagorean theorem, as Rick already mentioned, of course: on a right triangle, if the legs are 4 and 3 then the hypotenuse is 5.

For 16:9 sets, for height multiply by 1/2 and for width multiply by 8/9. This is only approximate: on a right triangle, if the legs are 16 and 8 then the hypotenuse is sqrt(16^2+9^2), which is approximately 18.36; I'm rounding this down to 18. But it will do for a rough calculation.

#### HeyNow^

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Thanks everyone. I'm trading in my 61" 4:3 and getting a 61" 16:9. I am hoping I made the correct decision.

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