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Discussion Starter · #1 ·
What are the width and length dimensions of a 61" 16:9 screen? And a 61" 4:3 screen?
 

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Quote:
Originally posted by RickZ:
61" 16:9 screen? Roughly 53" W by 30" H

61" 4:3 screen? Roughly 49" W by 37" H


Based on x**2+y**2=z**2.

Now calculate the area of each screen:

16:9 screen = 53 * 30 = 1590 sq. in.

4:3 screen = 49 * 37 = 1813 sq. in.


So, maybe the "widescreen" should in reality be called the "short screen". http://www.avsforum.com/ubb/eek.gif



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You can fit a 65" 16:9 inside a 73" 4:3.


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Turn the lights down and the sound up!
 

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61" 16:9 screen? Roughly 53" W by 30" H

61" 4:3 screen? Roughly 49" W by 37" H


Based on x**2+y**2=z**2.


------------------

Turn the lights down and the sound up!
 

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Although the CaveCreations link will do all the calculations for you, sometimes it's helpful to be able to do quick calculations on the road, so ...


For 4:3 sets, for height multiply by 3/5 and for width multiply by 4/5. This is just the Pythagorean theorem, as Rick already mentioned, of course: on a right triangle, if the legs are 4 and 3 then the hypotenuse is 5.


For 16:9 sets, for height multiply by 1/2 and for width multiply by 8/9. This is only approximate: on a right triangle, if the legs are 16 and 8 then the hypotenuse is sqrt(16^2+9^2), which is approximately 18.36; I'm rounding this down to 18. But it will do for a rough calculation.
 

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Discussion Starter · #7 ·
Thanks everyone. I'm trading in my 61" 4:3 and getting a 61" 16:9. I am hoping I made the correct decision.
 
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