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Your wording seems incomplete to comment accurately on. Would you mind saying what you just said, but a different way?
It may appear that way, but that's not the case. The only difference is where the jumpers are located, the rear of the speaker or the rear of the receiver. That might have some effect if electron waves didn't pass through insulated wire at approximately 130,000 miles per second, but since they do it doesn't.The crossover in a bi-wire setup actually occurs at the amp side.
Do you mean to say "bi-amp?" My speakers are bi-amped, so the speakers have no cross-overs. The amps do all of the work.
Yes there have been a few mathematical demonstrations of this phenomena. But at the end of the day most will agree it makes no audible difference.Presuming you are talking about bi-wire to passive crossovers at the speaker end... yes, you will be measuring different current drawer going to the different sides/drivers. Thus the different EMF on either peer of cables.
+1, you can mathematically predict it, and you can measure it. It's the main argument made by cable crooks to justify why you should pay them for two sets of cables. But you can't hear it. If you could it would show up on a measured speaker response and THD chart. That crucial bit of data never makes its way into cable crook advertising copy.Yes there have been a few mathematical demonstrations of this phenomena.
Electromagnetic fields are created by current flow.The EMF (voltage) is usually the same, esp. when using the same amplifier.
A current probe simply reveals different currents flowing through the differing load impedances of woofers versus tweeters and their filter networks.