Quote:
Originally posted by nrubenstein
You need to use ANSI lumens for that number. Peak-white lumens are more to impress than anything else. |
I do not believe that ANSI lumens would work in that equation. My projector puts out 240 ANSI lumens. Using the above equation, I would only get 12 sq. ft of screen area at 20 ft. lamberts. That is a 3'x4' screen, or a 60" diagonal. I am fairly certain that the image would be amazingly bright on a 5' diagonal screen with 8" guns on full output.
This equation works with peak-white output. Sure, you could modify the equation to work with ANSI lumens, but many digital projectors don't report ANSI Lumens, which would make it impossible to calculate.
I used this equation for my digital PJ, an NEC LT150, which running 48 sq. feet full panel at 2.6 gain yielded 370 lumens required to acchieve 20 ft. lamberts. The projector is 700 lumens, but I turned off the white segment and painted the color wheel, plus ran a filter. My best guestimate is that I should be around 350-400 lumens now. The picture is quite acceptable to all but die hard CRT fans. Even still, it is not a brightness issue that would be objectionable.
14-20 Ft. is desireable for proper viewing conditions
Ft Lamberts=Peak White Lumens X Screen Gain / Total Square Footage of Screen
If this is off base, I would like to know, but it has worked so far and would like to know before I get myself in a pickle with a screen that will give me a suntan or a picture that looks like I accidentall forgot to remove my welding hood.
Besides, don't ANSI lumens include some areas of the screen as black? Wouldn't that mean that having blacks as black as possible reduce your lumen output, even if the peak white output is the same? And trust me, I don't want 14-20 ft. lamberts of screen luminescence when the screen is all black.
Mike