distance from screen * tan(15) = 1/2 screen
Ex: 10' * 0.268 = 2.68' (half screen)
=> 5.36'
Ex: 10' * 0.268 = 2.68' (half screen)
=> 5.36'
-
Get an exclusive sneak peek into our new project. >>> Click Here
-
Our native mobile app has a new name: Fora Communities. Learn more.
Math question
I'm not sure I have the words right. Anyway, I think I read somewhere that the average viewer can watch a screen with a maximum off center horizontal axis of 30 degrees. That is, the total horizontal viewing "angle" is 60 degrees. Similarly, the vertical off-center axis is 15 degrees.
If I assume 30 degrees off-axis is a horizontal maximum, it forms a triangle. What is the formula, given the distance from the screen, of how wide 1/2 the screen can be? I'm trying to get an estimate of a reasonable 16x9 sized screen given 10 feet distance.
Take Aim
If I assume 30 degrees off-axis is a horizontal maximum, it forms a triangle. What is the formula, given the distance from the screen, of how wide 1/2 the screen can be? I'm trying to get an estimate of a reasonable 16x9 sized screen given 10 feet distance.
Take Aim
- Status
- Not open for further replies.
1 - 3 of 3 Posts
Are there some "official" opinions regarding these horizontal and vertical maximum angles? I'd like to find something in print. Thanks.
Take Aim
Take Aim
1 - 3 of 3 Posts
- Status
- Not open for further replies.
AVS Forum
A forum community dedicated to home theater owners and enthusiasts. Come join the discussion about home audio/video, TVs, projectors, screens, receivers, speakers, projects, DIY’s, product reviews, accessories, classifieds, and more!
Full Forum Listing
Top Contributors this Month
View All
WilliamR
975 Replies
BASSAHOLIC
508 Replies
bass addict
394 Replies
Recommended Communities
