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Discussion Starter · #1 ·
Does any one know the throw distance for a 100" diagonal screen? Projector Central has not updated its site for this projector.


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cai
 

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Hi Cai-

For a 16:9 100" the throw distance is:

Max= 17'11"

Min= 13'2"


Formula is a follows:


y1(Max)= (0.05510x-0.04593) X 3.28

y2(Min)= (0.04068x-0.04369) X 3.28


where x = Screen size (diag)(inches) and

y = Projection distance (feet)


Hope this helps.




[This message has been edited by Gladiator (edited 09-29-2001).]
 

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Discussion Starter · #3 ·
This was a quick reply. Thank you very much. This formula simplifies the task as it allows me to compute the distance for various screen sizes.


Again, great information.


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cai
 
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