I had nothing else to do this evening (god my life is so dull!) and so I downloaded
the manual for the XV-Z9000 from Sharp's website and did some calculatin'.
A screen with an aspect ratio of 16:9 and a width of 102" will have a height of 57.375" and a diagonal measurement of 117".
Using Sharp's
maximum projector distance formula of
Lmaxfeet = (0.0524
x - 0.0447) * 3.28
where
x is the screen diagonal measurement in inches, we get ((0.0524 * 117) - 0.447) * 3.28 = 18.64 feet.
Using Sharp's
minimum projector distance formula of
Lminfeet = (0.0436x - 0.0447) * 3.28
where
x is the screen diagonal measurement in inches, we get ((0.0436 * 117) - 0.447) * 3.28 = 15.27 feet.
So, if you want to have a 102" wide screen with a 16:9 aspect ratio, you will need to have a projector lens-to-screen distance of between 15'-3" and 18'-8".