I have searched through many threads but I am still unclear how to calculate screen size and projector location from throw distance. In particular, I am looking at the Sharp 9000 with a throw of 1 to 1.3. My viewing distance is about 110 inches and was planning on a 16:9 screen with a width between 73-80 inches (83-91 diagonal). The screen width to view distance would be 1.4 to 1.5 times (perhaps a little large http://www.avsforum.com/ubb/smile.gif ) Given the above how does I calculate projector position. There is a beam in my ceiling that I need to avoid....
Mike
Mike