[E-A-G-L-E-S]

I often see people post about how a 58" plasma has xx% for viewing area than a 50". Or a 52" lcd has xx% more than a 46".


Is there a referenced article or calculator to determine this or just a simple math problem that I can't think of how to set-up?

 

[Ballz2TheWallz]



Quote:
Originally Posted by E-A-G-L-E-S /forum/post/12950766


I often see people post about how a 58" plasma has xx% for viewing area than a 50". Or a 52" lcd has xx% more than a 46".


Is there a referenced article or calculator to determine this or just a simple math problem that I can't think of how to set-up?

http://cavecreations.com/tv2.cgi

 

[E-A-G-L-E-S]

That's great, thanks so much!

 

[ErikD7]

I made a quick and dirty Excel sheet that takes the diagonal measurement and calculates the horizontal and vertical dimensions of the screen as well as area. PM me and I'll be happy to email it to you.


Basically, for any 16:9 tv, the area is .4273*(d^2), where d = diagonal measurement. So for a 58" tv,


area = .4273 (58*58), or about 1437 sq. in.

 

[digital_dilemma]



Quote:
Originally Posted by Ballz2TheWallz /forum/post/12950985

http://cavecreations.com/tv2.cgi

Great post!

 

[Wolfe_CH]

This one is excellent as well:
http://tvcalculator.com/


- Chris